Find the product of `z_(1)` and `z_(2)`
If `z_(1)=2(cos.(pi)/(3)+isin.(pi)/(3))` and `z_(2)=3(cos.(2pi)/(3)+isin.(2pi)/(3))`

If z=cos((pi)/(3))-isin((pi)/(3)) then z^(2)-z+1=....

If z_(1)=sqrt(2)((cos pi)/(4)+i sin((pi)/(4))) and z_(2)=sqrt(3)((cos pi)/(3)+i sin((pi)/(3))) then |z_(1)z_(2)|=

z=cos(pi/6)+isin(pi/6)=?

z=5(cos((7pi)/6)+isin((7pi)/6))=?

(cos""(pi)/(6)+isin""(pi)/(6))^(1//2)+(cos""(pi)/(6)-isin""(pi)/(6))^(11//2)

If z= cos (pi)/(3) - i sin (pi)/(3) then z^(2)-z+1 is equal to

If z^(n) = cos"" (n pi)/(3) + isin"" (n pi)/(3), then z_(1), z_(2) …. Z_(6) is

If z_(1) = sqrt(2)(cos""(pi)/(4) + "" i sin""(pi)/(4)) and z_(2) = sqrt(3)(cos""(pi)/(3) + i sin""(pi)/(3)) , then |z_(1)z_(2)| is

If z_(1)= sqrt(2)(cos ""(pi)/(4)+ isin""(pi)/(4))" and "z_(2)= sqrt(3)(cos ""(pi)/(3)+ isin"" (pi)/(3)) , then |z_(1)z_(2)| is

Convert z=(i-1)/("cos"(pi)/(3)+"isin"(pi)/(3)) in polar form.