If A is a square matrix for which `a_(ij)=i^(2)-j^(2)`, then matrix A is

A=[a_(ij)]_(3xx3) is a square matrix so that a_(ij)=i^(2)-j^(2) then A is a

Let A=[a_(ij)] is a square matrix of order 2 where a_(ij)=i^(2)-j^(2) . Then A is (i) Skew - symmetric matrix (ii) Symmetric matrix (iii) Diagonal matrix (iv) None of these

If A=[a_(ij)] is a square matrix of even order such that a_(ij)=i^(2)-j^(2), then A is a skew- symmetric matrix and |A|=0 (b) A is symmetric matrix and |A| is a square (c) A is symmetric matrix and |A|=0 (d) none of these

If A=[a_(ij)] is a square matrix such that a_(ij)=i^(2)-j^(2), then write whether A is symmetric or skew-symmetric.

If A=[a_(ij)] is a square matrix of even order such that a_(ij)=i^(2)-j^(2), then

If A=[a_(i j)] is a square matrix of even order such that a_(i j)=i^2-j^2 , then (a) A is a skew-symmetric matrix and |A|=0 (b) A is symmetric matrix and |A| is a square (c) A is symmetric matrix and |A|=0 (d) none of these

If A is a square matrix such that a_(ij)=(i+j)(i-j), then for A to be non-singular the order of the matrix can be .

The element a_(ij) of square matrix is given by a_(ij)=(i+j)(i-j) then matrix A must be

The element a_(ij) of square matrix is given a_(ij) = (i+j) (i - j) , then matrix A must be a)Skew - symmetric matrix b)Triangle matrix c)Symmetric matrix d)Null matrix