The space between parallel plate capacitors is filled with four dielectrics of equal dimensions but of dielectric constants `K_(1), K_(2), K_(3)andK_(4)` respectively. If K is the dielectric constant of a single dielectric that must be filled between capacitor plates to have the same capacitance between A and B. Then we must have

The capacitance of a capacitor, filled with two dielectrics of same dimensions but of dielectric constants K_1 and K_2 respectively as shown will be -

A parallel plate capacitor with square plates is filed with four dielectrics of dielectric constants K_(1),K_(2),K_(3),K_(4), arranged as shown in the figure. The effective dielectric constant K will be :

A parallel -plate capacitor of area A , plate separation d and capacitance C is filled with four dielectric materials having dielectric constant k_(1), k_(2), k_(3) and k_(4) as shown in the figure below. If a single dielectric materical is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by

A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A "metre"^(2) and the separtion is t metre. The dielectric constants are K_(1) and K_(2) , respectively. Its capacitance in farad will be

If the gap between the plates of a parallel plate capacitor is filled with medium of dielectric constant k=2 , then the field between them

Half of the space between parallel plate capacitor is filled with a medium of dielectric constant K parallel to the plates . if initially the capacity is C, then the new capacity will be :