Find the number of divisors of the number `2^5 3^5 5^3 7^3` of the form `(4n+1), n in N uu {0}`

The number of divisors of the natural number N where N=2^(5)x3^(5)x5^(2)x7^(3) of the form 4n+2,n in W is

The total number of divisors of the number N=2^(5).3^(4).5^(10).7^(6) that are of the form 4K+2, AAK in N is equal to

The number of odd divisor of the number N=2^(10). 3^5 .7^2, are 16 b. 17 c. 18 d. 20

Find the number of divisors of the number N=2^(3).3^(5).5^(7).7^(9) which are perfect squares.

The number of positive divisors of 2^(5)3^(6)7^(3) is

Total number of divisors of N=2^(5)*3^(4)*5^(10)*7^(6) that are of the form 4n+2,n ge 1 , is equal to

Number of divisors of 2^2 . 3^3 . 5^3 . 7^5 of the form 4n+1', is (A) 46 (B) 47 (C) 96 (D) none of these

If n=10800, then find the a. total number of divisors of n. (b) The numberof even divisors. (c) The number of divisors of the form 4m+2. (d) The number of divisors which are multiples of 15.

" Total number of divisors of "N=3^(5).5^(7)*7^(9)" that are of the form "4k+1" ,is equal to "

Every number is one of the forms 5n, 5n pm 1, 5n pm 2 .