Two partical tied to different strings are whirled in a horizontal circle as shown in figure. The ratio of lengths of the string so that they complete their circular path with equal time priod is:

A stone is tied to the end of a string of length 1 and whirled in a horizental circle. When the string breaks then stone

A stone tied to a string of length l is whirled in a horizontal circle at a constant angular speed omega in a circle of radius r. If the string makes an angle theta with vertical then the tension in the string is :

A stone of mass 0.2 kg is tied to one end of a string of length 80cm Holding the other end, the stone is wirled into a vertical circle. What is the minimum speed of the stone at the lowest point so that it just completes the circle What is the tension in the string at the lowest point of the circular path ? . (g =10^(-2)) .

A particle of mass m is tied to a string of length L and whirled into a horizontal plan. If tension in the string is T then the speed of the particle will be :

IF a stone is tied to one end of the string and whirled in verticle circle, then the tension in the string at the lowest point is equal to

A small steel shphere tied at the end of a string is whirled in a horizontal circle with uniform angular velocity omega the string is suddently pulled so that the radius of the circle is halved .If omega_(2) is the angular velocity then

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^2 where A is a constant, r is the instantaneous radius fo the circle and n=....