Let (:a(n):) be a sequence given by a(n+...

Let `(:a_(n):)` be a sequence given by `a_(n+1)=3a_(n)-2*a_(n-1)` and `a_(0)=2,a_(1)=3` then the value of `sum_(n=1)^(oo)(1)/(a_(n)-1)` equals
(A) `1`
(B) `(1)/(2)`
(C) `2`
D) `4`

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