Home
Class 11
PHYSICS
A cricket ball of mass 150 g has an init...

A cricket ball of mass 150 g has an initial velocity `bar(u)=(3hati-4hatj)ms^(-1)` and a final velocity `bar(v)=-(3hati-4hatj)ms^(-1)` after being hit. The change in momentum (final momentum -initial momentum) is `("in kg ms"^(-1))`

Promotional Banner

Similar Questions

Explore conceptually related problems

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150g has an initial velocity (3 hati + 4hatj)ms^(-1) and a final velocity upsilon = -(3hati + 4hatj)ms^(-1) after beigh hit The change in momentum (final momentum initial momentum) is (in kg ms^(-1) )

A cricket ball of mass 100g has initial velocity vec u = (3hati + 4hatj)ms and final velocity vec v = (-3hati -4hatj)ms after being hit by the bat.The magnitude of the impulse on the bat by the ball will be

A body of mass 0.8 kg has intial velocity (3hati-4hatj) ms^(-1) and final velocity (-6hatj+2hatk) ms^(-1) . Find change in kinetic energy of the body?

A particle has an initial velocity (6hati+8hatj) ms^(-1) and an acceleration of (0.8hati+0.6hatj)ms^(-2) . Its speed after 10s is

A body of mass 5 kg is moving with velocity of v=(2hati+6hatj)ms^(-1) at t=0s. After time t=2s, velocity of body is (10 hati+6 hatj) , then change in momentum to body is

In a reference frame a man A is moving with velocity (3hati-4hatj)ms^(-1) and another man B is moving with velocity (hati+hatj)ms^(-1) relative to A. Find the actual velocity of B.

A particle of mass m moving with a velocity (3hati+2hatj)ms^-1 collides with another body of mass M and finally moves with velocity (-2hati+hatj)ms^-1 . Then during the collision

A body of mass 5 kg starts from the origin with an initial velocity bar(u)=(30hati+40hatj)ms^(-1) .If a constant force (-6hati-5hatj)N acts on the body, the time in velocity, which the y-component of the velocity becomes zero is.

A force applied on a particle of mass 2 kg changes its velocity from (hati + 2 hatj ) ms^(-1) "to" (4hati +6hatj )ms^(-1) ​. The work done by the force in this process is :-