If the function `(cos x+ K sin x)/(2cos x+3sin x)` is decreasing in Its domain then `K_(in)`
(A) `((3)/(2),oo)`
(B) `(0,(3)/(2))`
(C) `(-oo,(3)/(2))`
(D) `(-oo,0)`

If the function (cos x+K sin x)/(2cos x+3sin x) is decreasing in its domain then K is

If the function f(x)=2x^(2)-kx+5 is increasing on [1,2], then k lies in the interval (a) (-oo,4)(b)(4,oo)(c)(-oo,8)(d)(8,oo)

If the function f(x)=x^(2)-kx+5 is increasing on [2,4], then (a) k in(2,oo)(b)k in(-oo,2)(c)k in(4,oo)(d)k in(-oo,4)

The domain of definition of the function f(x)=ln{x}+sqrt(x-2{x}) is: (where { } denotes fractional part function) (A) (1,oo) (B) (0,oo) (C) (1,oo)~I^(+) (D) None of these

lim_ (x rarr oo) (cos x + sin x) / (x ^ (2))

The domain of the function f(x)=1/(sqrt(|x|-x)) is: (1) (-oo,oo) (2) (0,oo (3) (-oo,""0) (4) (-oo,oo)"-"{0}

The function f(x)=log x-(2x)/(x+2) is increasing for all A) x in(-oo,0) , B) x in(-oo,1) C) x in(-1,oo) D) x in(0,oo)

lim_ (x rarr oo) (2x + 7sin x) / (4x + 3cos x) =

The range of the function f(x)=(sin(pi[x]))/(x^(2)+1) (Where [ ] denotes greatest integer function) is (A) {0} (B) (-oo,oo) (C) (0,1) (D) R-{0}

If the equation sin x+cos(k+x)+cos(k-x)=2 has real solutions,then sin k can be(A)(1)/(4)(B)(1)/(sqrt(2))(C)(3)/(4)(D)-(3)/(4)