A particle is projected vertically with speed V from the surface of the earth . Maximum height attained by the particle , in term of the radius of earth R,V and g is ( V `lt` escape velocity , g is the acceleration due to gravity on the surface of the earth )

If an object is projected vertically upwards with speed , half the escape speed of earth , then the aximum height attained by it is [ R is radius of earth ]

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

A particle is throws vertically upwards from the surface of earth and it reaches to a maximum height equal to the radius of earth. The radio of the velocity of projection to the escape velocity on the surface of earth is

What will be the acceleration due to gravity at height h if h gt gt R . Where R is radius of earth and g is acceleration due to gravity on the surface of earth

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.