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If the lines (x+4)/3=(y+6)/5=(z-1)/(-2) ...

If the lines `(x+4)/3=(y+6)/5=(z-1)/(-2)` and `3x-2y+z+5=0=2x+3y+4z-k` are coplanar, then `k=` `-4` (2) 3 (3) 2 (4) 4 (5) 1

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