When a radiation of wavelength λ1 falls on a surface,the maximum kinetic energy of the emitted photoelectrons is K_(1) For a radiation of wavelength λ2the maximum kinetic energy is K_(2) .If λ1=λ2/2 ,then 9work function is not zero)

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

When a radiation of energy 5eV falls on a surface,the emitted photoelectrons have a maximum kinetic energy of 3eV .The stopping potential is

If ultraviolet radiation of 6.2 eV falls of an aluminium surface , then kinetic energy of the fastest emitted electrons is (work function = 4.2 e V)

When a given electromagnetic radiation illuminates the metal surface , the maximum kinetic energy of photoelectrons depends on

When an electro-magnetic radiation is incident on the surface of metal, maximum kinetic energy of photoelectron depends on-

When light of 2.5 eV falls on a metal surface, maximum kinetic energy of electron is T. If incident radiation of 4 eV falls on same metal surface, maximum kinetic energy of electrons is doubled. The work function of metal is

If light of wavelength lambda_(1) is allowed to fall on a metal , then kinetic energy of photoelectrons emitted is E_(1) . If wavelength of light changes to lambda_(2) then kinetic energy of electrons changes to E_(2) . Then work function of the metal is

In a photo-emissive cell, with exciting wavelength lambda_1 , the maximum kinetic energy of electron is K. If the exciting wavelength is changed to lambda_2 , the maximum kinetic energy of electron is 2K then

The photoelectric threshold for a certain metal surface is 330 Å . What is the maximum kinetic energy of the photoelectrons emitted , if radiations of wavelength 1100 Å are used ?