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int(0)^(25)[sqrt(x)]dx...

`int_(0)^(25)[sqrt(x)]dx`

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int_(0)^(1)x+sqrt(x)dx=

int_(0)^(4){sqrt(x)}dx=

int_(0)^(1)sqrt(x)dx=

int_(0)^(2) sqrt(2-x)dx .

int_(0)^(4)x sqrt(x) dx=

int_(0)^(1)sqrt(x+1) dx =

int_(0)^(2)(1)/(sqrt(x))dx

int_(0)^(1)sqrt(x(1-x))dx equals

int_(0)^(4) x sqrt(4-x)dx

- int_(4)^(0)(sqrt(x)-2)dx