Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

Position of a particle moving along x-axis is given by x=6t-t^(2)+4 , where x is in metre and t is in second. Which of the following is correct?

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

[" Position of particle "],[" moving along x axis is "],[" given by "x=t^(3)+4t+2" .Here "x],[" is in metre and "t" is in "],[" seconds.Find "],[" displacement of particle "],[" from "t=2" to "t=4" sec."]

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

The position of a particle moving along the y-axis is given as y=3t^(2)-t^(3) where y is in , metres and t is in sec.The time when the particle attains maximum positive y position will be