A lorry and a car moving with the same `KE` are brought to rest by applying the same retarding force. Then

A lorry and a car, moving with the same kinetic energy are brought to rest by application of brakes which provied equal retarding forces. Which one of them will come to rest in a shorter distance ?

A truck and a car moving with the same KE are brought to rest by the application of brakes which provide equal retarding force. Which of them will come to rest in a shorter distance ?

A lorry and a car moving with the same kinetic energy are brought to rest by the application of brakes which provides equal retarding forces. Which of them will come to rest in a shorter distance?

A truck and a car moving with the same kinetic energy are brought to rest by the application of brakes which provide equal retarding forces. Which of them will come to rest in a shorter distance?

Two unequal masses P and Q moving along straight lines are brought to rest by applying equal retarding forces. If P moves twice the time as Q, but goes only (1//3)^(rd) of the distance covered by Q before coming to rest, the ratio of their initial velocities is

A car and a truck,are moving with same K .E. or same momentum or same velocity and applying same retarding force.Their stopping distances are S_(1) and S_(2) respectively:

STATEMENT-1: A bus and a car having the same kinetic energy are brought to rest by the applications of brakes. Assume that on application of brakes, rotational motion of wheels ceases and both may stop in dead heat. because STATEMENT-2: Retardation for both bus and truck must be same.

Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare ?

A car moving with a velocity v is stopped within a distance x by applying a retarding force F. If the speed of the car is doubled, then the force required to stop the car with the same distance is