An a.c. source of voltage `V = 100 sin 100 pi t`. Is connected to a resistor of `(25)/(sqrt2) ohm`. What is the r.m.s value of current (in ampere) through the resistor ?

An Ac source of volatage V=100 sin 100pit is connected to a resistor of resistance 20 Omega .The rms value of current through resistor is ,

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is , power factor is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is total charge transferred through resistor in long time is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is average value of current for half cycle is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is ,total charge transferred in 1/100 second is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is the averge value for half cycle is

An Ac source of volatage V=100 sin 100pit is connected to a resistor of ressistance 20 Omega The rsm value of current through resistor is ,total heat generated in one cycle is

An alternating voltage V = 400 sin (500 omega t)V is connected to a 0.2 kOmega resistor, what will be the rms value of current ?