A cell constituted by two electrondes `A(E_(A//A^(+))^(@)= -0.35 V)` and `B (E_(B//B^(+))^(@)=0.42 V)`.
Calculate the emf of the cell.

A cell constituted by two electrodes A(E_(A+//A)^(0) = 0.35V) and B(E_(B+//B)^(0) = +0.42V) has value of E_("cell")^(0) equal to _____

A cell constituted by two electrodes A (E^(@)A//A+0.35V) and B(E^(@)B//B=-0.42V) Has value of E_("Cell")^(@) equal to

E_(cu)^(0)=0.34 and E_(zn)^(0)=-0.76V . Calculate E_("cell")^(0) .

E_(Cu)^(0)=+0.34V and E_(Ag)^(0)=+0.8V" calculate "E_(cell")^(0) .

Calculate e.m.f. of the cell containing nickel and copper electrodes. Given that : E_(Ni^(2+)//Ni)^(@)=-0.25 V , E_(Cu^(2+)//Cu)^(@)=+0.34 V.