यदि E और F स्वतन्त्र घटनाएँ हो और `P(E ) = 0.3` तथा `P(F ) = 0.4` तो ज्ञात कीजिए :
`P (E cup F),`

IF P (E ) =0.6 ,P( F) =0.3 and P (E nn F )=0.2 , find P(F|E) .

If P(E ) = 0.8, P(F) = 0.5 and P(E cap F) = 0.4 then P( E//F)=….......

If P (E) = 0.40, P (F) = 0.35, P (E uu F) = 0.55, then P(F/E) is

Consider the following relations for two events E and F: 1. P (E cap F) ge P(E ) + P (F) - 1 2. P (E cup F) = P (E ) + P(F) + P (E cap F) 3. P (E cup F) le P (E ) + P (F) Which of the above relations is/are correct ?

If P(E) = 0.40, P(F) = 0.35 and P(EuuF)=0.55 , find P(E|F) .

Given that E and F are events such that P(E) = 0.8, P(F) = 0.7, P (E nn F) = 0.6. Find P ( E | F )

Two events E and F are independent . If P ( E) =0.3 , P (E cup F) = 0.5 then P ( E | F ) - P (F |E) equals

Given that E and F are events such that P (E) = 0. 6 , P (F) = 0. 6 , P(F) = 0. 3 and P(EnnF)= 0. 2 , find P (E|F) and P (F|E) .

Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E cup F) = 0.7 , find P(E|F) and P(F|E).