A,B,C and D have position vectors a,b,c and d, respectively, such that a-b=2(d-c). Then,

A ,B ,C and D have position vectors vec a , vec b , vec c and vec d , respectively, such that vec a- vec b=2( vec d- vec c)dot Then a. A Ba n dC D bisect each other b. B Da n dA C bisect each other c. A Ba n dC D trisect each other d. B Da n dA C trisect each other

A ,B ,C and D have position vectors vec a , vec b , vec ca n d vec d , respectively, such that vec a- vec b=2( vec d- vec c)dot Then a. A Ba n dC D bisect each other b. B Da n dA C bisect each other c. A Ba n dC D trisect each other d. B Da n dA C trisect each other

A,B,C and D are four points in a plane with position vectors vec a,vec b,vec c and vec d, respectively,such that (vec a-vec d)*(vec b-vec c)=(vec b-vec d)*(vec c-vec a)=0 Then point D is the of triangle ABC

Show that the found points A,B,C,D with position vectors vec a,vec b,vec c,vec d respectively such that 3vec a-2vec b+5vec c-6vec d=vec 0 ,are coplanar .Also,find the position vector of the point of intersection of the line segments AC and BD.

If vec a,vec b,vec c are the position vectors of points A,B,C and D respectively such that (vec a-vec d)*(vec b-vec c)=(vec b-vec d)*(vec c-vec a)=0 then D is the