Let `n AM's` are inserted between - `7 and 65` If the ratio of `2^(nd)` and `7^(th)` means is `1:7`, then `n` is equal to

n A.MI's are inserted between n and 3n+2 then 10 th A.M. is

n A.M.\'s are inserted between 1 and 31 such that the ratio of the 7th and (n-1) th means is 5:9. Find n.

n A.M.'s are inserted between 1 and 31 such that the ratio of the 7 th and (n-1) th means is 5:9. Find n.

There are m A.M.s' between 1 and 31 . If the ratio of the 7^(th) and (m-1)^(th) means is 5:9 then m=

If n A.M.'s are inserted between 20 and 80 such that the ratio of first mean to the last mean is 1:3 then the value of n is

n arithmetic means are inserted between 3 and 17 such that ratio of first and the last means is 1: 3, find n.

'n' A.M's are inserted between a and 2b, and then between 2a and b. If p^(th) mean in each case is a equal, a/b is equal to

'n' A.M's are inserted between a and 2b, and then between 2a and b. If p^(th) mean in each case is a equal, a/b is equal to

'n' A.M's are inserted between a and 2b, and then between 2a and b. If p^(th) mean in each case is a equal, a/b is equal to

If n arithmetic means are inserted between 1 and 31 such that the ratio of the first mean nd nth mean is 3:29 then the value of n is 10 b.12 c.13 d.14