Home
Class 11
CHEMISTRY
The factor by which the degree of ionisa...

The factor by which the degree of ionisation of `200mL` of `0.1M` benzoic acid solution `(K_(a) = 4 xx 10^(-5))` changes on addition of `100mL` of `0.2M HC1` is:

Promotional Banner

Similar Questions

Explore conceptually related problems

The factor by which the degree of ionisation of 200mL of 0.1M benzoic acid solution (K_(a) = 4 xx 10^(-5)) changes on addition of 100mL of 0.2M HCl is:

In the titration of 25.0 mL of 0.1 M aqueous acetic acid (K_(a) = 1.8 xx 10^(-5)) with 0.1 M NaOH (aq), the pH after addition of 10.0 mL of tirant is

Which causes a largest change in pH on addition to 20ml 0.1 M acetic acid solution ?

A monoprotic acid in 0.1 M solution has K_(a)=1.0xx10^(-5) . The degree of dissociation for acid is

On adding 100mL of 10^(-2) M NaOH solution to 100mL of 0.01M Triethyl amine solution (K_(b)=6.4xx10^(-5)) ,change in pH of solution will be:

100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then (K_a= 1.2 xx 10^(-6))

100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then (K_a= 1.2 xx 10^(-6))

Calculate the degree of ionisation and concentration of H_(3)O^(+) ions in a solution of 0.01 M formic acid (K_(a)= 2.1 xx 10^(-4))