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The equation of the circle passing throu...

The equation of the circle passing through the origin which cuts of intercept of length 6 and 8 from the axes is `x^2+y^2-12 x-16 y=0` b. `x^2+y^2+12 x+16 y=0` c. `x^2+y^2+6x+8y=0` d. `x^2+y^2-6x-8y=0`

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