Equation of the circle through origin which cuts intercepts of length `a\ a n d\ b` on axes is a. `x^2+y^2=a x+b y=0` b. `x^2+y^2-a x-b y=0` c. `x^2+y^2+b x+a y=0` d. none of these

Equation of the circle through origin which cuts intercepts of length a and b on axes is a.x^(2)+y^(2)=ax+by=0 b.x^(2)+y^(2)-ax-by=0cx^(2)+y^(2)+bx+ay=0 d.none of these

The equation of the circle passing through the origin which cuts of intercept of length 6 and 8 from the axes is a. x^2+y^2-12 x-16 y=0 b. x^2+y^2+12 x+16 y=0 c. x^2+y^2+6x+8y=0 d. x^2+y^2-6x-8y=0

The equation of the circle passing through the origin which cuts of intercept of length 6 and 8 from the axes is x^(2)+y^(2)-12x-16y=0 b.x^(2)+y^(2)+12x+16y=0cx^(2)+y^(2)-3x+4y=2=0 d.none of these

Show that equation of the circle passing through the origin and cutting intercepts a and b on the coordinate axes is x^2 + y^2 - ax - by =0

Show that equation of the circle passing through the origin and cutting intercepts a and b on the coordinate axes is x^2 + y^2 - ax - by =0

The equation of diameter of a circle passing through origin is x+y=1 and the greatest distance of any point of the circle from the diameter is sqrt(5) , then an equation of the circle is: (A) x^2+y^2-2x+4y=0 (B) x^2+y^2-4x+2y=0 (C) x^2+y^2+2x-2y=0 (D) none of these

The equation of the circle through the points of intersection of x y -1 -0, x y -2x-4 y l 0 and touching the line x 2y 0, is (B) x y 2 x+20 (C) x y (D) 2 (x2 y x 2

A circle with center (a , b) passes through the origin. The equation of the tangent to the circle at the origin is (a) a x-b y=0 (b) a x+b y=0 b x-a y=0 (d) b x+a y=0

The equation of a line through (2, -4) which cuts the axes so that the intercepts are equal in magnitude is : (A) x+y+2=0 (B) x-y+2=0 (C) x+y+6=0 (D) x+y-6=0

The equation of a line through (2, -4) which cuts the axes so that the intercepts are equal in magnitude is : (A) x+y+2=0 (B) x-y+2=0 (C) x+y+6=0 (D) x+y-6=0