A tuning fork arrangement (pair) produces `4 beats//sec` with one fork of frequrncy `288cps`. A little wax is placed on the unknown fork and it then produces `2 beats//sec`. The frequency of the unknown fork is

A tuning fork arrangement (pair) produces 4 beats//sec with one fork of frequency 288cps . A little wax is placed on the unknown fork and it then produces 2 beats//sec . The frequency of the unknown fork is

A tuning fork arrangement (pair) produces 4 beats//sec with one fork of frequency 288cps . A little wax is placed on the unknown fork and it then produces 2 beats//sec . The frequency of the unknown fork is

A tuning fork arrangement (pair) produces 4beats/with one fork of frequency 288 c.p.s. A little wax is placed on the unknown fork and it then produces 2 beats/s. The frequency of the unknown fork is

A tuning fork arrangement (pair) produces 4beats/with one fork of frequency 288 c.p.s. A little wax is placed on the unknown fork and it then produces 2 beats/s. The frequency of the unknown fork is

A tuning fork produces 4 beats per sec with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it produces 2 beats per second. The frequency of unknown fork is

When two tuning fork were sounded together 5 beats/s were produced, with one fork of frequency 282 cps. On another fork of unknown frequency a little wax is placed and as a result, the pair now produces 3 beats/s. Determine the freqency of the unknown fork.

A tuning fork having n = 300 Hz produces 5 beats/s with another tuning fork. If impurity (wax) is added on the arm of known tuning fork, the number of beats decreases then calculate the frequency of unknown tuning fork.

A tuning fork having n = 300 Hz produces 5 beats/s with another tuning fork. If impurity (wax) is added on the arm of known tuning fork, the number of beats decreases then calculate the frequency of unknown tuning fork.