A : The general solution of `sin x = -1` is `n pi + (-1)^(n)(3pi)/(2), n in Z`
R : The principal solution of sin x = 0 lies in `[-pi//2, pi//2]`

A : The general solution for cos theta = 3//2 is theta = 2n pi pm Cos^(-1)(3//2) R : The general solution for cos theta = k is theta = 2n pi pm alpha, n in Z where 'alpha' is principal value, alpha in [0, pi] and |k|le 1

The general solution of cos x cos6x=-1 is x=(2n+1)pi,n in Zx=2n pi,quad n in Zx=n pi,n in Z(d) none of these

I : The solution of 7 sin^(2)x + 3 cos^(2)x=4 is {n pi pm pi//6 : n in Z} II : The solution of tan^(2)theta = 3 is {n pi pm pi//3 : n in Z}

Prove that the general solution of sin theta=sin alpha is given by : theta=n pi+(-1)^(n)alpha,n in Z

If the general solution of sin5x=cos2x is of the form a_(n)*(pi)/(2) for n=0,+-1,+-2,... then a_(n)=

Principal solutions of the equation sin2x+cos2x=0, where pi

General solution for |sin x|=cos x is 2n pi+(pi)/(4),n in I(b)2n pi+-(pi)/(4),n in1n pi+(pi)/(4),n in1(d) none of these

If x!=(n pi)/(2),n in I and (cos x)^(sin)(2x-3sin x+2)=1, then find the general solution of x.

Statement -1 the solution of the equation (sin x)/(cos x + cos 2x)=0 is x=n pi, n in I Statement -2 : The solution of the equation sin x = sin alpha , alpha in [(-pi)/(2),(pi)/(2)] x={npi+(-1)^(n)alpha,n in I}

Statement -1 the solution of the equation (sin x)/(cos x + cos 2x)=0 is x=n pi, n in I Statement -2 : The solution of the equation sin x = sin alpha , alpha in [(-pi)/(2),(pi)/(2)] x={npi+(-1)^(n)alpha,n in I}