In the arrangement shown, `W_(1) = 200N, W_(2) = 100 N,mu = 0.25` for all surfaces in contact. The block `W_(1)` just slides under the block `W_(2)`

Calculate the Force (F) required to cause the block of mass m_(1) = 20 kg just to slide under the block of mass m_(2) = 10 kg [ coefficient of friction mu = 0*25 for all surfaces ]

Calculate the Force (F) required to cause the block of mass m_(1) = 20 kg just to slide under the block of mass m_(2) = 10 kg [ coefficient of friction mu = 0*25 for all surfaces ]

Calculate the force P required to cause the block of weight W_(2)=200N just to slide under the block of weight W_(1)=100N shown in figure-2.43. What is the tension in the string AB and the normal forces acting between the blocks and that applied by ground on W_(2) ? Surfaces of the blocks in contact are rough and the frictional force between the two blocks is 25 N and that between lower block and ground is 75 N Take g = 10 m//s^(2) .

Calculate the force P required to cause the block of weight W_(2)=200N just to slide under the block of weight W_(1)=100N shown in figure-2.83. What is the tension in the string AB ? Coefficient of friction mu = 0.25 for all surfaces in contact. [90 N, 20sqrt(2)N]

Block A of weight 500 N and block B of weight 700 N are connected by rope pulley system as shown. The largest weight C that can be suspended without moving block A and B is W . The coefficient of friction for all plane surfaces of contact is 0.3 . The pulleys are ideal. Find (W)/(90) .

Two weights W_(1) and W_(2) in equilibrium and at rest, are suspended as shown in figure. Then the ratio (W_(1))/(W_(2)) is :

Two weights W_(1) and W_(2) in equilibrium and at rest, are suspended as shown in figure. Then the ratio (W_(1))/(W_(2)) is :

A block of weight W is suspended from a spring balance. The lower surface of the block rests on a weighing mechine. The spring balance reads W_(1) and the weighing machine reads W_(2)(W,W_(1),W_(2) are in the same unit).

There are two blocks of masses m_(1) and m_(2) , m_(1) is placed on m_(2) on a table which is rotating with an angular velocity omega about the vertical axis . The coefficent of friction between the block is mu_(1) and between m_(2) and table is mu_(2) (mu_(1) lt mu_(2)) if block are placed at distance R from the axis of ratation , for relative sliding between the surface in contact , find the a. friction force at the contacting surface b. maximum angular speed omega

There are two blocks of masses m_(1) and m_(2) , m_(1) is placed on m_(2) on a table which is rotating with an angular velocity omega about the vertical axis . The coefficent of friction between the block is mu_(1) and between m_(2) and table is mu_(2) (mu_(1) lt mu_(2)) if block are placed at distance R from the axis of ratation , for relative sliding between the surface in contact , find the a. friction force at the contacting surface b. maximum angular speed omega