A particle having a charge 100 times that of an electron is revolution in a circular path of radius 0.4 m, with 1 rev/s. What is the magnitude of the magnetic field produced at its center?

A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

A particle having charge 100 times that of an electron is revolving in a circular path by radius 0.8 m with one rotation per second. The magnetic field produced at the centre is,

A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre . The value of the magnetic field produced at the centre will be ( mu_(0)= permeability for vacuum)

A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre . The value of the magnetic field produced at the centre will be ( mu_(0)= permeability for vacuum)

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100V/m makes it to move in a straight path, then the mass of the particle is ( Given charge of electron = 1.6 xx 10^(-19)C )