In a given series LCR circuit `R=4Omega, X_(L)=5Omega` and `X_(C)=8Omega`, the current

In an L-C-R series circuit R = 10Omega, X_(L) = 8Omega and X_(C) = 6Omega the total impedance of the circuit is -

In an L-C-R series circuit R = 10Omega, X_(L) = 8Omega and X_(C) = 6Omega the total impedance of the circuit is -

In a series A.C. circuit , R=100Omega , X_(L)=300Omega and X_(C )=200Omega . The phase difference between the applied e.m.f. and the current will be

In series LCR circuit 3 = Omega X_(L) = 8 Omega, X_(C) = 4 Omega , the impendance of the circuit is:

In an L.C.R series circuit R = 1Omega, X_(L) = 1000Omega" and "X_(C) = 1000Omega . A source of 100 m.volt is connected in the circuit the current in the circuit is

In a series L-C-R circuit X_(L)350 Omega, X_(C)=200 Omega and R = 150 Omega .

In an L-C-R circuit , R=sqrt7Omega, X_L=11Omega and X_C=8Omega , then the value of impedance =______

In an AC series circuit, R = 10 Omega, X_L=20Omega and XC=10Omega .Then, choose the correct options

In an AC series circuit, R = 10 Omega, X_L=20Omega and XC=10Omega .Then, choose the correct options