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From a certain apparatus, the diffusion ...

From a certain apparatus, the diffusion rate of hydrogen has an average value of `28.7cm^(3)//s`. The diffusion of another gas under the same condition is measured to have an average rate of `7.2cm^(3)//s`. Identify the gas.

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From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3)s^(-1) . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2cm^(3)s^(-1) . Identify the gas (NCERT).

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^3 s^-1 . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^3 s^-1 . Identify the gas

From a certain apparatus,the diffusion rate of hydrogen has an average value of 28.7 cm^3s^(-1) .The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^3s^(-1) .Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same condition is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas.

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas. [Hint : Use Graham's law of diffusion: R_(1)//R_(2) = (M_(2) //M_(1) )^(1//2) , where R_(1), R_(2) , are diffusion rates of gases 1 and 2, and M_(1) and M_(2) their respective molecular masses. The law is a simple consequence of kinetic theory.]

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm^(3) s^(-1) . The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm^(3) s^(-1) . Identify the gas. [Hint : Use Graham's law of diffusion: R_(1)//R_(2) = (M_(2) //M_(1) )^(1//2) , where R_(1), R_(2) , are diffusion rates of gases 1 and 2, and M_(1) and M_(2) their respective molecular masses. The law is a simple consequence of kinetic theory.]