If `"Tan"^(-1)1/(1+2)+"Tan"^(-1)1/(1+(2)(3))+"Tan"^(-1)1/(1+(3)(4))+..."Tan"^(-1)1/(1+n(n+1))=Tan^(-1)theta`, then `theta` =

If tan^(-1)(1/(1+1. 2))+tan^(-1)(1/(1+2. 3))+.... +tan^(-1)(1/(1+n.(n+1)))=tan^(-1)theta, then find the value of thetadot

tan^(-1)(1/2)+tan^(-1)(1/3)=tan^(-1)(theta) then theta is

tan^(-1)((1)/(1+1.2))+tan^(-1)((1)/(1)+2.3)+...+tan^(-1)((1)/(1+n(n+1)))=tan^(-1)theta then find the value of theta.

if tan^-1(1/(1+1*2))+tan^-1(1/(1+2*3))+.............+tan^-1(1/(1+n*(n+1)))=tan^-1theta then find the value of theta

"tan"^(-1)1/3+"tan"^(-1)1/7+……+tan^(-1)(1/(n^(2)+n+1))=

tan^(-1)((3)/(n))+tan^(-1)((4)/(n))=(pi)/(2)

If theta=tan^(-1)((1)/(10))+tan^(-1)((1)/(9))+...+tan^(-1)(1)+tan^(-1)(2)+...+tan^(-1)(10)+tan^(-1)(11) .If tan theta=(m)/(n) (where m,n are coprime) then the value of (m+n) is equal to

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=