If `2x^2+lambdax y^+2y^2+(lambda-4)x+6y-5=0,` is the equation of a circle, then its radius is :

If 2x^(2)+lambda xy^(+)2y^(2)+(lambda-4)x+6y-5=0 is the equation of a circle,then its radius is :

If 3x^(2)+2lambda xy + 3y^(2)+(6-lambda)x+(2lambda-6)y-21=0 is the equation of a circle, then its radius is

If 3x^(2)+2lambda xy + 3y^(2)+(6-lambda)x+(2lambda-6)y-21=0 is the equation of a circle, then its radius is

If 2x^2+lambdaxy+2y^2 +(lambda-4)x + 6y-5=0 represents a circle, then its radius is:

Find the number of integral values of lambda for which x^2+y^2+lambdax+(1-lambda)y+5=0 is the equation of a circle whose radius does not exceed 5.

Find the number of integral values of lambda for which x^2+y^2+lambdax+(1-lambda)y+5=0 is the equation of a circle whose radius does not exceed 5.

If the equation lambda x^2+(2 lambda-3)y^2-4x-1=0 represents a circle, then its radius is :