If `1/3+1/2+1/x=4,` then `x=?` `5/(18)` (b) `6/(19)` (c) `(18)/5` (d) `(24)/(11)`

If 1/3+1/2+1/x=4, then x=? (a) 5/(18) (b) 6/(19) (c) (18)/5 (d) (24)/(11)

If x/2-4=x/3-1, then x= (a)3 (b) 6 (c)18 (d) 2

If x : y=1:1,\ t h e n\ (3x+4y)/(5x+6y)= (a) 7/(11) (b) (17)/(11) (c) (17)/(23) (d) 4/5

If x : y=1:1,\ t h e n\ (3x+4y)/(5x+6y)= (a) 7/(11) (b) (17)/(11) (c) (17)/(23) (d) 4/5

The coordinates of the middle point of the chord cut-off by 2x-5y+18=0 by the circle x^(2)+y^(2)-6x+2y-54=0 are (1,4) (b) (2,4) (c) (4,1) (d) (1,1)

The coordinates of the middle point of the chord cut-off by 2x-5y+18=0 by the circle x^2+y^2-6x+2y-54=0 are (1,4) (b) (2,4) (c) (4,1) (d) (1,1)

The coordinates of the middle point of the chord cut-off by 2x-5y+18=0 by the circle x^2+y^2-6x+2y-54=0 are (a) (1,4) (b) (2,4) (c) (4,1) (d) (1,1)

When ((1)/(2)-(1)/(4)+(1)/(5)-(1)/(6)) is divided by ((2)/(5)-(5)/(9)+(3)/(5)-(7)/(18)), the result is 2(1)/(18) (b) 3(1)/(6)(c)3(3)/(10) (d) 5(1)/(10)

5(5)/(6)-3(8)/(9)-?=1(2)/(3)(b)(3)/(2)(c)(17)/(18) (d) 3

If d/(dx) {f(x)}=1/(1+x^2) then d/(dx){f(x^3)} is a) (3x)/(1+x^3) b) (3x^2)/(1+x^6) c) (-6x^5)/(1+x^6)^2 d) (-6x^5)/(1+x^6)