A force of `(3 hati + 4 hatj)` Newton acts on a body and it by `(3 hati + 4 hatj)m`. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (3hati+4hatj) metre. The work done by the force is

A force (3hati+4hatj) newton acts on a boby and displaces it by (2hati+3hatj) metre. The work done by the force is

A force vecF= (3hati+4hatj) N acts on a body and displaces it by vecS= (3hati+4hatj)m . The work done (W= vecF*vecS ) by the force is :

A force vecF= (3hati+4hatj) N acts on a body and displaces it by vecS= (3hati+4haj)m . The work done (W= vecF*vecS ) by the force is :

A particle acted by constant forces 4 hati + hatj - 3 hatk and 3 hati + hatj - ahtk is displaced from the point hati + 2 hatj + 3 hatk to the point 5 hati + 4 hatj + hatk. The total work done by the forces is :

Due to a force of (6hati+2hatj)N the displacement of a body is (3hati-hatj)m , then the work done is