The infinitesimal angular displacement of a particle performing circular motion is a vetor because its obeys

The infinitesimally angular displacement delta theta in uniform circular motion is

A particle performing uniform circular motion has

A particle performing uniform circular motion has

A particle performing uniform circular motion has

The angular displacement of a particle performing circular motion is theta = (t^3)/60 - t/4 where theta is in radian and 't' is in seconds. Then the angular velocity and angular accleration of the particle at the end of 5 s will be

The angular displacement of a particle performing circular motion is theta = (t^3)/60 - t/4 where theta is in radian and 't' is in seconds. Then the acceleration of the particle at the end 10 s will be

The angular displacement of a particle performing circular motion is theta=(t^(3))/(60)-(t)/(4) where theta is in radian and 't' is in second .Then the angular velocity and angular acceleraion of a particle at the end of 5 s will be

The angular displacement of a particle performing circular motion is theta=(t^(4))/(60)-(t)/(4) where theta is radian and 't' is in seconds. Then the acceleration of a particle at the end of 10 s will be

The rate of change of angular displacement in uniform circular motion is .