The three points whose position vectors are i + 2j + 3k, 3i + 4j + 7k and -3i - 2j - 5k

The triangle formed by the three points whose position vectors are 2i + 4j -k , 4i +5j + k and 3i + 6j - 3k , is

The points whose position vectors are 2i + 3j + 4k, 3i + 4j + 2k and 4i + 2j + 3k are the vertices of

The area of the triangle formed by the points whose position vectors are 3i + j 5i + 2j + k, I - 2j + 3k is

I : The three points with position vectors i - 2j + 3k, 2i + 3j - 4k and -7j + 10k are collinear. II : The vectors a - 2b + 3c, 2a + 3b - 4c, -7b + 10c are coplanar.

If the points whose position vectors are -2i + 3j + 5k, i + 2j + 3k, lambda i - k are collinear, then lambda =

A unit vector perpendicular to the plane passing through the points whose position vectors are 2i-j+5k,4i+2j+2k and 2i+4j+4k is

If the points whose position vectors are 3i-2j-k,2i+3j-4k,-i+j+2k and 4i+5j+lambda k lie on a plane then lambda is equal to (A)-(146)/(17) (B) (146)/(17) (C) -(17)/(146) (D) (17)/(146)