" In a series LR circuit,"x_(2)=3R" .Now a capacitor with "X_(C)=R" is added in series.Ratio of new to old power factor is "

In series LR circuit, X_(L) = 3 R . Now a capacitor with X_(C ) = R is added in series. The ratio of new to old power factor

In series LR circuit, X_(L) = 3 R . Now a capacitor with X_(C ) = R is added in series. The ratio of new to old power factor

In series L-R circuit, X_L=R . Now a capacitor with X_C=R is added in series. New power factor

In series L-R circuit, X_L=R . Now a capacitor with X_C=R is added in series. New power factor

In L-C-R series circuit

In L-C-R series circuit

An ac circuit has an inductor and a resistor of resistance R in series, such that X_(L) =3 R. Now, a capacitor is added in series such that X_(C)=2 R. The ratio of new power factor with the old power factor of the circuit is sqrt5 : x. The value of x is_________

In a series resonant L-C-R circuit, the power factor is

In a series LR circuit X_(L) = R and power factor of the circuit is P_(1) . When capacitor which capacitance C such that X_(L) =X_(C) is put in series , the power factor becomes P_(2) .Calculate P_(1)//P_(2)

(i) An a.c. Source of voltage V = V_(0) " sin " omegat is connected to a series combination of L,C and R . Use the phasor diagram to obtain expression for impedance of the circuit and phase angle between voltage and current . Find the condition when current will be phase with the voltage . What is the circuit in this condition called ? (ii) In a series LR circuit X_(L) = R and power factor of the circuit is P_(1) . When capacitor which capacitance C such that X_(L) =X_(C) is put in series , the power factor becomes P_(2) .Calculate P_(1)//P_(2)