If `z=3- 4i` is turned `90^@` in anti clock direction then new position of z is

Let P be a point represented by the complex number Z. Rotate OP (O is the origin) through pi//2 in the anti clockwise direction, the new position of the complex number is represented by

Vector z- 3-4i is rotated at 180 angle in anti clock wise direction and its length is increased to two and half xx.In new position z is

The complex number 3-4i is rotated by 90^(@) in the anticlockwise direction about origin. The complex number in new position is

Ram is facing North -west . He turns in clockwise direction by 90^(@) , then 180^(@) in the anti- clock -wise direction and them another 90^(@) in the same direction and the another 90^(@) in the same direction . Which direction is he facing now ?

If z=sqrt(2)- isqrt(2) si rotated through an angle 45^(@) in the anti-clockwise direction about the origin, then the co-ordianates of its new position are

In the Argand plane, the vector z = 4 - 3i is turned in the clockwise sense through 180^(@) and stretched 3 times. The complex number represented by new vector is

If z_(1) , z_(2) and z_(3) are the vertices of DeltaABC , which is not right angled triangle taken in anti-clock wise direction and z_(0) is the circumcentre, then ((z_(0)-z_(1))/(z_(0)-z_(2)))(sin2A)/(sin2B)+((z_(0)-z_(3))/(z_(0)-z_(2)))(sin2C)/(sin2B) is equal to

If z_(1) , z_(2) and z_(3) are the vertices of DeltaABC , which is not right angled triangle taken in anti-clock wise direction and z_(0) is the circumcentre, then ((z_(0)-z_(1))/(z_(0)-z_(2)))(sin2A)/(sin2B)+((z_(0)-z_(3))/(z_(0)-z_(2)))(sin2C)/(sin2B) is equal to

If z_(1) , z_(2) and z_(3) are the vertices of DeltaABC , which is not right angled triangle taken in anti-clock wise direction and z_(0) is the circumcentre, then ((z_(0)-z_(1))/(z_(0)-z_(2)))(sin2A)/(sin2B)+((z_(0)-z_(3))/(z_(0)-z_(2)))(sin2C)/(sin2B) is equal to

In the Argand plane, the vector z = 4 - 3i is turned in the clockwise sense through 180^@ and stretched three times. The complex number represented by the new vector is