The expression `(t a n A)/(1-cot A)+(cot A)/(1-t a n A)` can be written as `sin A cos A+1` b. `s e c A\ cos e c A+1` c. `t a n A+cot A` d. `s e c A+cos e c A`

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1

The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1

Prove the following identity: (t a n A)/(1-cot A)+(cot A)/(1-t a n A)=(s e c A\ cos e c\ A+1)

Prove: (cos e c\ A)/(cos e c\ A-1)+(cos e c\ A)/(cos e c\ A+1)=2sec^2A

Prove the following identity: (s e c A\ s e c B+t a n AtanB)^2-(s e c A\ t a n B+t a n A s e c B)^2=1

If cos(A-B)=3/5a n d\ t a n AtanB=2, t h e n cos A\ cosB=1/5 b. cosA\ cos B=\ -1/5 c. sin A\ sin B=\ -1/5 d. sin A\ sin B=\ -1/5

The expression ((cos A-cos B)/(sin A-sin B))^m+((sin A+sin B)/(cos A-cos B))^m where m in N has the value- a.2cot^m((A-B)/2), if m i s od d b. 0, if m i s od d c. 2cot^("m")((A-B)/2), if m i s e v e n d. 0, if m i s e v e n