" What and "1=|[b+c,a,a],[b,c+a,b],[c,c,a+b]|

Show that |[1,b c, a(b+c)],[1,c a, b(c+a)],[1,a b ,c(a+b)]|=0 .

Prove that: |[a+b, b+c, c+a],[b+c,c+a,a+b],[c+a,a+b,b+c]|=2|[a,b,c],[b,c,a],[c,a,b]|

prove without expanding, |[(a-b),1,a],[b-c,1,b],[c-a,1,c]|=|[a,1,b],[b,1,c],[c,1,a]|

Prove that : |[a+b+c,-c,-b],[-c, a+b+c, -a],[-b,-a,a+b+c]|= 2(a+b)(b+c)(c+a)

If Delta_(1)=|(b+c,c+a,a+b),(c+a,a+b,b+c),(a+b,b+c,c+a)| and Delta_(2)=|(a,b,c),(b,c,a),(c,a,b)| then (Delta_(1))/(Delta_(2))= _______

If Delta_(1)=|(b+c,a-b,a),(c+a,b-c,b),(a+b,c-a,c)| and Delta_(2)=|(a,b,c),(b,c,a),(c,a,b)| then Delta_(1)-Delta_(2) equual

Show that |{:(b+c,c+a,a+b),(c+a,a+b,b+c),(a+b,b+c,c+a):}|=2|{:(a,b,c),(b,c,a),(c,a,b):}|

Prove that |[a+b+c, -c, -b],[-c, a+b+c, -a],[-b, -a, a+b+c]|=2(a+b)(b+c)(c+a)

prove |[1, b c, a(b+c)],[ 1, c a, b(c+a)],[ 1, a b, c(a+b)]|=0