" (v) वक्र "5x^(2)+5y^(2)-11x-9y-12=0," बिन्दु "(1,3)" पर "

To remove the first degree terms in the following equations origin should be shifted to the another point then calculate the new origins from list - II {:(" List - I "," List - II "),("(A) "x^(2)-y^(2)+2x+4y=0,"(1) (5,-7) "),("(B) "4x^(2) +9y^(2)-8x+36y + 4 = 0,"(2) (1,-2) "),("(C) "x^(2) + 3y^(2) + 2x + 12y + 1 = 0,"(3) (-1,2) "),("(D) "2(x-5)^(2)+3(y+7)^(2)=10,"(4) (-1,-2) "),(,"(5) (-5,7) "):} The correct matching is

If 2x^(2)+3y+5y^(2)+x+9=0," then "((dy)/(dx))at(-1,-1) is

I. 2x^(2)-11x+15 = 0" "II.4y^(2)+13y+9 = 0

O, A, B are vertices of triangle whose sides are given by (5x+12y)^(2)-3(12x-5y)^(2)=0, 5x+12y-78=0 then AB =

The equation of the circle passing through the point of intersection of the circle x^2+y^2=4 and the line 2x+y=1 and having minimum possible radius is (a) 5x^2+5y^2+18 x+6y-5=0 (b) 5x^2+5y^2+9x+8y-15=0 (c) 5x^2+5y^2+4x+9y-5=0 (c) 5x^2+5y^2-4x-2y-18=0

The equation of the circle passing through the point of intersection of the circle x^2+y^2=4 and the line 2x+y=1 and having minimum possible radius is (a) 5x^2+5y^2+18 x+6y-5=0 (b) 5x^2+5y^2+9x+8y-15=0 (c) 5x^2+5y^2+4x+9y-5=0 (c) 5x^2+5y^2-4x-2y-18=0

The equation of the circle passing through the point of intersection of the circle x^(2)+y^(2)=4 and the line 2x+y=1 and having minimum possible radius is (a) 5x^(2)+5y^(2)+18x+6y-5=0(b)5x^(2)+5y^(2)+9x+8y-15=0(c)5x^(2)+5y^(2)+4x+9y-5=0(c)5x^(2)+5y^(2)-4x-9y-5=0(c)5x^(2)+5y^(2)-4x-2y-18=0

Find the like terms in the following 9x^(2)y, 5x, 7y^(2), - 3x^(2), - 5x, 9xy, 11y^(2) .