`(x+2y +1) dx - (2x + 4y +3)dy = 0, x+2y = u`

(2x -2y +3) dx - (x -y +1) dy = 0 , x -y =u

If x^(3) dy + xy dx = x^(2) dy + 2y dx , y (2) = e and x gt 1 , then y(4) is equal to .

Which of the following is a homogeneous differential equation? (A) (4x + 6y + 5) dy - (3y + 2x + 4) dx = 0 (B) (x y)dx-(x^3+y^3)dy=0 (C) (x^3+2y^2)dx+2x ydy=0 (D) y^2dx+(x^2+x y-y^2)dy=0

Solve the following differential equation (2x + y + 1) dx + (4x + 2y —1) dy = 0 .

(2x -2y+3) dx -(x-y+1) dy=0 , " when" x=0, y=1

Solve: (xy ^ (3) + y) dx + 2 (x ^ (2) y ^ (2) + x + y ^ (4)) dy = 0

The solution of 2 (y + 3) - x y(dy)/(dx) = 0 with y =-2, when x =1 is :a) (y + 3) = x ^(2) b) x ^(2) (y + 3) = 1 c) x ^(4) (y + 3) = 1 d) x ^(2) ( y +3) ^(2) = e ^(y +2)

[x sin^(2)((y)/(x)) - y] dx + x dy = 0, y = (pi)/(4) when x = 1