We know that balancing of a chemical equation is entirely bases on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of consevation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction:
`ABC_(3) rarr AB+C_(2)`
On applying POAC for A , B and C and related the equations , we get : `(n_(ABC_(3)))/(2) =(n_(AB))/(2) =(n_(C_(2)))/(3)`
(`n_(x)` : number of moles of X)
Thus , the cofficients of `ABC_(3)` , AB and `C_(2)` in the balanced chemical equation will be 2,2 and 3 respectively and the balanced chemical equation can be represented as ,
`2ABC_(3) rarr 2AB + 3C_(2)` Which of the following statements jis correct balanced chemical equation,
`pA+qB_(2) rarr rA_(2)B_(5)`

We know that balancing of a chemical equation is entirely bases on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of consevation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction: ABC_(3) rarr AB+C_(2) On applying POAC for A , B and C and related the equations , we get : (n_(ABC_(3)))/(2) =(n_(AB))/(2) =(n_(C_(2)))/(3) ( n_(x) : number of moles of X) Thus , the cofficients of ABC_(3) , AB and C_(2) in the balanced chemical equation will be 2,2 and 3 respectively and the balanced chemical equation can be represented as , 2ABC_(3) rarr 2AB + 3C_(2) For the unbalanced chemical equation given below, which of the following statement is correct? X+Y_(2) rarr XY_(3)

We know that balancing of a chemical equation is entirely bases on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of consevation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction: ABC_(3) rarr AB+C_(2) On applying POAC for A , B and C and related the equations , we get : (n_(ABC_(3)))/(2) =(n_(AB))/(2) =(n_(C_(2)))/(3) ( n_(x) : number of moles of X) Thus , the cofficients of ABC_(3) , AB and C_(2) in the balanced chemical equation will be 2,2 and 3 respectively and the balanced chemical equation can be represented as , 2ABC_(3) rarr 2AB + 3C_(2) If in the above question, the atomic masses of X and Y are 10 and 30 respectively, then the mass of XY_(3) formed when 120 g of Y_(2) reacts completely with X is:

We know that balancing of a chemical equation is entirely bases on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of consevation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction: ABC_(3) rarr AB+C_(2) On applying POAC for A , B and C and related the equations , we get : (n_(ABC_(3)))/(2) =(n_(AB))/(2) =(n_(C_(2)))/(3) ( n_(x) : number of moles of X) Thus , the cofficients of ABC_(3) , AB and C_(2) in the balanced chemical equation will be 2,2 and 3 respectively and the balanced chemical equation can be represented as , 2ABC_(3) rarr 2AB + 3C_(2) If in the above question, the atomic masses of X and Y are 10 and 30 respectively, then the mass of XY_(3) formed when 120 g of Y_(2) reacts completely with X is:

Balancing a chemical equation is based on

A balanced chemical equation is based on

We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction.So, POAC can also act as a technique for balancing a chemical equation.For example, for a reaction : ABC_3toAB+C_2 On applying POAC for A,B&C and relating the 3 equation, we get : (.^nABC_3)/2=(.^nAB)/2=(.^n_(c_2))/3 ( n_x : number of moles of x) Thus, the coefficients of ABC_3 ,AB & C_2 in the balanced equation with be 2,2 & 3 respectively and the balanced chemical equation can be represented as : 2ABC_3to2AB+3C_2 Now answer the following questions : If the weight ratio C and O_2 presents 1:2 and both of reactants completely consume and form CO and CO_2 and we will obtain a gasous mixture of CO and CO_2 .What would be the weight ratio of CO and CO_2 in mixture.