सिद्ध कीजिएः की `(x+1/x)^(2n)` के प्रसार में मध्य पद `(1.3.5....(2n-1))/(n!).2^(n)` है

Prove that the term independent of x in the expansion of (x+1/x)^(2n) \ is \ (1. 3. 5 ... (2n-1))/(n !). 2^n .

Prove that the middle term in the expansion of (1+x)^(2n)" is " (1.3.5....(2n-1))/(n!).2^(n)x^(n)

Prove that the term independent of x in the expansion of (x+(1)/(x))^(2n) is (1.3.5....(2n-1))/(n!)*2^(n)

Show that the middle term in the expansion of (1 + x)^(2n) is (1.3.5.........(2n - 1))/(n!)2^(n)x^(n) , where n is a positive integer.

Show that the middle term in the expansion of (x+1)^(2n)" is " (1.3.5. ......(2n-1))/(n!).2^(n).x^(n).

Show that the middle term in the expansion of (x-1/x)^(2n) is (1.3.5.7....(2n-1))/(n!)(-2)^n

Show that the middle term in the expansion of (1+x)^(2n)" is "(1.3.5. ..(2n-1))/(n!)(2x)^(n).

Show that the middle term in the expansion of (1+x)^(2n)" is "(1.3.5. ..(2n-1))/(n!)(2x)^(n).

If the middle term of (1+x)^ (2n) is (1.3.5….(2n-1)k)/(n!) then k=

Show that the middle term in the expansion of (1+x)^(2n) is ((1.3.5...2n-1)))/(n!)2^(n)x^(n), where n is a positive integer.