The sum of the coefficients of the first three terms in the expansion of`(x-3/(x^2))^m ,x!=0,`m being a natural number, is 559. Find the term of the expansion containing `x^3`.

Explanation

To solve the problem, we need to find the term in the expansion of \((x - \frac{3}{x^2})^m\) that contains \(x^3\), given that the sum of the coefficients of the first three terms in the expansion is 559. Let's break this down step by step.

### Step 1: Write the General Term
The general term \(T_{r+1}\) in the expansion of \((x - \frac{3}{x^2})^m\) can be expressed as:
\[ T_{r+1} = \binom{m}{r} x^{m-r} \left(-\frac{3}{x^2}\right)^r \]
This simplifies to:
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