In Fig. 5-23a, a cord pulls a box of sea biscuits up along a frictionless plane inclined at angle `theta=30.0^(@)`. The box has mass m = 5.00 kg, and the force from the cord has magnitude T = 25.0 N. What is the box's acceleration a along the inclined plane ?

Explanation

To find the acceleration of the box along the inclined plane, we will use Newton's second law of motion. Let's break down the steps:

### Step 1: Identify the forces acting on the box
The forces acting on the box are:
1. The tension (T) in the cord pulling the box up the incline, which is given as \( T = 25.0 \, \text{N} \).
2. The gravitational force acting downward, which can be decomposed into two components:
- Perpendicular to the incline: \( mg \cos(\theta) \)
- Parallel to the incline: \( mg \sin(\theta) \)
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