A 1.50kg object is subjected to three forces that give it an acceleration `vec(a)=-(8.00"m"//"s"^(2))hatj`. If two of the three forces are `vec(F)_(1)=(30.0N)hati+(16.0N)hatj` and `vec(F_(2))=-(12.0N)hati+(8.00N)hatj`, find the third force.

Explanation

To find the third force acting on the object, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The equation can be expressed as:

\[ \vec{F}_{\text{net}} = m \cdot \vec{a} \]

### Step 1: Identify the Given Values
- Mass of the object, \( m = 1.50 \, \text{kg} \)
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