A firefighter who weighs 689 N slides down a vertical pole with an acceleration of `2.00" m"//"s"^(2)`, directed downward. What are the (a) magnitude and (b) direction (up or down) of the vertical force on the firefighter from the pole and the ( c ) magnitude and (d) direction of the vertical force on the pole from the firefighter ?

Explanation

To solve the problem step by step, we will analyze the forces acting on the firefighter and apply Newton's second law of motion.

### Step 1: Identify the forces acting on the firefighter
The forces acting on the firefighter are:
- The weight of the firefighter (W) acting downward, which is given as 689 N.
- The frictional force (F_k) exerted by the pole on the firefighter, which acts upward.

### Step 2: Write the equation of motion
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