An object weighs 2.50 kg. In time t, measured in seconds, the velocity of the object is given by `bar(v)=(7.00t hati+2.00t^(2)hatj)` m/s. At the instant the net force on the object has a magnitude of 35.0 N, what are the direction of the net force and the object's direction of travel ?

Explanation

To solve the problem, we need to determine the direction of the net force acting on the object and the direction of the object's travel at a specific time \( t \). The steps are as follows:

### Step 1: Determine the velocity vector
The velocity of the object is given by:
\[ \mathbf{v} = (7.00t) \hat{i} + (2.00t^2) \hat{j} \quad \text{(m/s)} \]

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