An elevator cab is pulled upward by a cable. The cab and its single occupant have a combined mass of 2000 kg. When that occupant drops a coin, its acceleration relative to the cab is `8.30" m"//"s"^(2)` downward. What is the tension in the cable?

Explanation

To solve the problem, we need to determine the tension in the cable pulling the elevator cab upward. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Given Information
- Combined mass of the elevator cab and occupant, \( m = 2000 \, \text{kg} \)
- Acceleration of the coin relative to the cab, \( a_{ce} = 8.3 \, \text{m/s}^2 \) (downward)

### Step 2: Understand the Accelerations
- The acceleration of the coin relative to the ground can be expressed as:
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