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A marble is dropped straight down from a...

A marble is dropped straight down from a distance h above the floor.
Let `F_(m)` = the magnitude of the gravitational force on the marble due to the Earth,
`F_(e)` = the magnitude of the gravitational force on the Earth due to the marble,
`a_(m)` = the magnitude of the acceleration of the marble toward the Earth,
`a_(e)` = the magnitude of the acceleration of the Earth toward the marble.
Which set of conditions is true as the marble falls toward the earth? Neglect any effects of air resistance.

A

`F_(m)=F_(e)` and `a_(m) lt a_(e)`

B

`F_(m) lt F_(e)` and `a_(m) gt a_(e)`

C

`F_(m) lt F_(e)` and `a_(m) = a_(e)`

D

`F_(m=F_(e)` and `a_(m) gt a_(e)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the forces acting on the marble and the Earth as the marble falls. ### Step-by-Step Solution: 1. **Identify the Forces**: - The gravitational force acting on the marble due to the Earth is denoted as \( F_m \). - The gravitational force acting on the Earth due to the marble is denoted as \( F_e \). 2. **Apply Newton's Third Law**: - According to Newton's Third Law, every action has an equal and opposite reaction. Therefore, the magnitudes of the forces are equal: \[ F_m = F_e \] 3. **Calculate the Gravitational Force on the Marble**: - The gravitational force acting on the marble is given by: \[ F_m = m \cdot g \] - Here, \( g \) is the acceleration due to gravity, which can be approximated as \( g = \frac{GM}{R^2} \) where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( R \) is the radius of the Earth. 4. **Calculate the Gravitational Force on the Earth**: - The gravitational force acting on the Earth due to the marble is: \[ F_e = M \cdot a_e \] - Here, \( a_e \) is the acceleration of the Earth toward the marble. 5. **Set the Forces Equal**: - Since \( F_m = F_e \), we can equate the two expressions: \[ m \cdot g = M \cdot a_e \] 6. **Determine the Acceleration of the Earth**: - Rearranging the equation gives: \[ a_e = \frac{m \cdot g}{M} \] - Since \( M \) (mass of the Earth) is much larger than \( m \) (mass of the marble), \( a_e \) will be very small compared to \( g \). 7. **Determine the Acceleration of the Marble**: - The acceleration of the marble toward the Earth is simply \( g \): \[ a_m = g \] 8. **Conclusion**: - The magnitudes of the gravitational forces \( F_m \) and \( F_e \) are equal. - The acceleration of the marble \( a_m \) is much greater than the acceleration of the Earth \( a_e \): \[ a_m > a_e \] - Therefore, the correct conclusion is that the magnitude of both forces is equal, but the acceleration of the Earth is much less than that of the marble. ### Final Answer: - The magnitude of the gravitational force on the marble due to the Earth \( F_m \) is equal to the magnitude of the gravitational force on the Earth due to the marble \( F_e \). - The acceleration of the marble \( a_m \) is much greater than the acceleration of the Earth \( a_e \).
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