In Fig. 25-7a switch S is closed to connect the uncharged capacitor of capacitance C =`0.25 mu F` to the battery of potential difference V=12V. The lower capacitor plate has thickness L=0.50 cm and face area A=`2.0 times 10^-4 m^2` and it consists of copper in which the density of conduction electrons is `n=8.49 times10^25` electrons/`m^3`. From what depth d within the plate (Fig.25-7b) must electrons move to the plate face as the capacitor becomes charged?

Explanation

To solve the problem, we need to find the depth \( d \) within the copper plate from which electrons must move to the plate face as the capacitor becomes charged. We will follow these steps:

### Step 1: Calculate the charge \( Q \) on the capacitor
The charge \( Q \) on a capacitor is given by the formula:
\[ Q = C \cdot V \]
Where:
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